Question

a) Draw the quadrilateral shown in the figure
b) Draw a triangle of the same area ​

Answer 1

Answer:

your answer is in the attachment

Answer 2

Step-by-step explanation:

Given: Figure

To find: Area of Quadrilateral and draw a triangle with same area.

Solution:

Step 1: There are two triangles in the Quadrilateral ABCD.

∆ABD and ∆BCD

Step 2: Write hero's formula

$area = \sqrt{s(s - a)(s - b)(s - c)}$

Area of ∆ABD:

Let a=5,b=7 and c=6

$s = \frac{5 + 6 + 7}{2} \\ \\ s = 9$

$area = \sqrt{9(9 - 5)(9 - 7)(9 - 6)} \\ \\ area = \sqrt{9 \times 4 \times 2 \times 3}$

area of ∆ABD=6√6 cm² =14.69 cm².

Area of ∆BCD:

here,

a=4, b=6 and c=3

$area = \sqrt{ 6.5(6.5 - 4)(6.5 - 6)(6.5 - 3) } \\ \\ area = \sqrt{6.5 \times 2.5 \times 0.5 \times 3.5}$

Area ∆BCD= 5.33 cm²

Step 3: Write area of ABCD

Area of ∆ABD+Area of ∆BCD

=14.67+5.33

=20.02 cm².

Step 4: Write the dimensions of triangle so that area of triangle will 20. 02cm²

Let the base of triangle is 10.01 cm

and it's height is 4 cm

Thus,

Area of triangle = 1/2×base×height

=1/2×10.01×4

=20.02 cm²

Hope it helps you.

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