Question

A drawer contains 4 red socks, 3 white socks, and 3 blue socks. Without looking, you select a sock at random, replace it, and select a second sock at random. What is the probability that the first sock is blue and the second sock is red?

Answer 1

Hey there mate !

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The correct answer is

(3/10) * (4/10)=3/25.

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Answer 2

Answer:

probability of selecting first sock blue and second sock red is 0.12

Step-by-step explanation:

given, there are 4 red socks, 3 white socks and 3 blue socks

total number of socks  = 10

one sick is selected at random, replaced and a second one is selected

total number of favorable outcomes = 10

probability of selecting first sock blue = P(B) = $\frac{3}{10}$

probability of selecting second sock red = P(R) = $\frac{4}{10}$

probability of selecting first sock blue and second sock red

 ⇒ P(B&R) = P(B) × P(R) = $\frac{3}{10}$ × $\frac{4}{10}$ = $\frac{12}{100}$ = $\frac{3}{25}$

⇒ P(B&R) = 0.12

Thus, probability of selecting first sock blue and second sock red is 0.12