Question

A dress requires 2.7 m of cloth. How many such dresses can be cut out from a piece of cloth measuring 45.9m?​

Answer 1

$\underline{ \underline{ \Large \sf { \pink{Given:}} } }$

• Metres of cloth required for one dress = 2.7 m

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$\underline{ \underline{ \Large \sf { \pink{To \: calculate:}} } }$

• How many such dresses can be cut out from a piece of cloth measuring 45.9m?

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$\underline{ \underline{ \Large \sf { \pink{Calculation:}} } }$

✰ Here, we are given that each dress requires 2.7 m of cloth. And, we have to find out the number of dresses that can be cut out from a piece of cloth measuring 45.9m.

~Firstly, we'll assume the number of dresses that can be cut out from a piece of cloth measuring 45.9m as "x". Then, we'll form a suitable algebraic equation. By solving that linear equation, we'll find the value of "x" i.e, the number of dresses that can be cut out from a piece of cloth measuring 45.9m.

Let the number of dresses be "x".

According to the question,

$\longmapsto \rm {Number \: of \: dresses \times 2.7 \: m = 45.9 \: m} \\ \\ \\ \longmapsto \rm {x \times 2.7 = 45.9 }$

Now, transpose 2.7 from LHS to RHS in in order to find the value of x. Remember! Whenever we apply transposition method in linear equations, the signs get changed. Example, 2.7 is in the multiplication form in LHS. When we'll transpose it to RHS, it'll become in the form of division.

$\longmapsto \rm {x = \dfrac{45.9}{2.7} } \\ \\ \\ \longmapsto \rm {x = \dfrac{459 \times 10}{27 \times 10 } } \\ \\ \\ \longmapsto \rm {x = \dfrac{4590}{270} } \\ \\ \\ \longmapsto \rm {x = \dfrac{459}{27} } \\ \\ \\ \longmapsto \underline{\boxed{ \pmb { \rm \red{x = 17 }} }}$

Henceforth,

• 17 dresses can be cut out from a piece of cloth measuring 45.9 m.

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