A drill rated at 20W drills a hole in 50sec in a metal cylinder of mass 50 gm. If all energy is converted into heat and sp heat capacity of metal is 0.8 jgm^-1C^-1. calculate the rise in tempatarure.
Answers
Given info : A drill rated at 20W drills a hole in 50sec in a metal cylinder of mass 50 gm. If all energy is converted into heat and sp heat capacity of metal is 0.8 j/g/°C.
To find : The rise in temperature is ..
solution : energy dissipated by drill machine = power × time
= 20W × 50 sec
= 1000 J
dissipated energy is converted into heat.
so, energy = mass of cylinder × specific heat capacity of metal × change in temperature
⇒1000 J = 50g × 0.8 J/g/°C × ∆T
⇒1000/40 = 25 = ∆T
Therefore the rise in temperature is 25°C.
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