A drilling machine is used to drill a hole in a
10 kg metal block. Power of the drilling
machine is 1 KW and it is used for 5 minutes.
If 4096 of the work done by the drilling
machine is converted into heat in the metal
block, the rise in its temperature is (specific
heat - 0.12 cal gm C and J = 4.2 J/Cal)
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Answer:
Given,
Mass = 10kg
Specific heat = 0.12cal gm = 502.416J kg
To find:-
Raise in temperature
By applying, Q = m.c.ΔT
ΔT = Q/mc
= 502.416/10×4.2
= 502.416/42
= 11.96°C.
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