Physics, asked by laharimama6789, 5 months ago

A drilling machine of power P watts is used
to drill a hole in copper block of mass M
kg. If the specific heat of copper is
s Jkg-'°C- and 40% of the power is lost
due to heating of the machne the rise in
the temperature of the block in T second
will be in °C)​

Answers

Answered by sudhanshup999
1

Answer:

Power of machine = P;

Energy used by machine in time 'T' = PT

Out of which 40% is wasted

i.e. Energy used on the block = 0.6PT=Q

This energy is used to heat the block

The rise in temperature is given by:

Q=mSΔT , M is the mass of the block and s is the specific heat capacity.

i.e.

ΔT=

Ms

Q

=

Ms

0.6PT

Answered by Anonymous
1

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