Question

a driver accelerates his car 1st at rate of 4m/s ^2 and then at the rate of 8m/s^2 . calculate the ratio of the force excerted by the engines ​

Answer 1

Answer:

2f1=f2

Explanation:

$f {1} = ma{1} \: \: \: (1) \\ f{2} = ma{2} \: \: \: (2) \\ now \: compare \: both \: equation \\ f{1} | f{2} = a{1} |a{2} \\ = 4 |8 = 1 |2 = 2 \: f{1} = f{2}$