Question

a driver accelerates his car first at rate of 1.8m/s2and then at the rate of 1.2 m/s2 calculate the ratio of the forces exerted by the engines

Answer 1

➡Force = mass × acceleration

here mass remains the same in both the cases

=> F1:F2 = ma1/ma2

=> F1:F2 = a1/a2

=> F1:F2 = 1.8/1.2 = 6/4 =3/2

hope it helps you...
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Answer 2

Answer:

$\dfrac{F_1}{F_2}=\dfrac{3}{2}$

Explanation:

It is given that,

Acceleration 1, $a_1=1.8\ m/s^2$

Acceleration 2, $a_2=1.2\ m/s^2$

Let F₁ and F₂ forces exerted by the engines. It can be calculated using the Newton's law of motion as :

$\dfrac{F_1}{F_2}=\dfrac{a_1}{a_2}$

$\dfrac{F_1}{F_2}=\dfrac{1.8}{1.2}$

$\dfrac{F_1}{F_2}=1.5$

$\dfrac{F_1}{F_2}=\dfrac{3}{2}$

So, the ratio of forces exerted by the engines are 3:2. Hence, this is the required solution.