Question

A driver accelerates his car first at the rate of 1.8 m/s2

, and then at the rate of 1.2 m/s2

.

Calculate the ratio of the force exerted by the engine in the two cases.​

Answer 1

Answer:

• Ratio between the forces exerted by engine in the two cases is 3 : 2

Explanation:

Given,

• A driver accelerates his Car first at, a₁ = 1.8 m/s² and then;  at the rate, a₂ = 1.2 m/s²

To find,

• Ratio of force exerted by the Engine in two cases

so,

Using formula

Force = mass × acceleration

Let, Mass of Car (with engine) = m

Force exerted by car on accelerating with rate of 1.8 m/s² (F₁)

→ F₁ = m a₁

→ F₁ = m × ( 1.8 )

Force exerted by car on accelerating with rate of 1.2 m/s² (F₂)

→ F₂ = m a

→ F₂ = m × ( 1.2 )  

Now,

→ F₁ / F₂ = [ m × ( 1.8 ) ] / [ m × ( 1.2 ) ]

→ F₁ / F₂ = 18 / 12

→ F₁ / F₂ = 3 / 2

therefore,

• Ratio between the forces exerted by engine in the two cases is 3 : 2 .

Answer 2

Answer:

Explanation:

Given,

A driver accelerates his Car first at, a₁ = 1.8 m/s² and then;  at the rate, a₂ = 1.2 m/s²

To find,

Ratio of force exerted by the Engine in two cases

so,

Using formula

Force = mass × acceleration

Let, Mass of Car (with engine) = m

Force exerted by car on accelerating with rate of 1.8 m/s² (F₁)

→ F₁ = m a₁

→ F₁ = m × ( 1.8 )

Force exerted by car on accelerating with rate of 1.2 m/s² (F₂)

→ F₂ = m a

→ F₂ = m × ( 1.2 )  

Now,

→ F₁ / F₂ = [ m × ( 1.8 ) ] / [ m × ( 1.2 ) ]

→ F₁ / F₂ = 18 / 12

→ F₁ / F₂ = 3 / 2

therefore,

Ratio between the forces exerted by engine in the two cases is 3 : 2 .