a driver accelerates his car first at the rate of 1.8m/s^2 and then at the rate of 1.2m/s^2 . the ratio of two forces exerted by the engine in the two cases will be ?
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Explanation:
Force is directly proportional to the acceleration.
F1/F2 = a1/a2
F1/F2 = 1.8/1.2
F1/F2 = 3/2
F1 : F2 = 3:2
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0
Answer:
The answer is 3:2
Explanation:
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