Question

a driver accelerates his car first at the rate of 4 m/s2 and then at the rate of 8 m/s2 . calculate the ration of the forces exerted by the engines?

Answer 1

Answer:

2:4as4:8

Explanation:

its very crazy question 4m/s2 :8m/s2 =2:4

Answer 2

RATIO IS 1 : 2 .

Given:

• Initial acceleration is 4 m/s²
• Final acceleration is 8 m/s²

To find:

Ratio of forces ?

Calculation:

We know that the force exerted by the Indians will be equal to the product of the mass of the car and the acceleration of the car.

$\therefore \: \dfrac{F_{1}}{F_{2}} = \dfrac{m \times a_{1}}{m \times a_{2}}$

$\implies \: \dfrac{F_{1}}{F_{2}} = \dfrac{ a_{1}}{ a_{2}}$

$\implies \: \dfrac{F_{1}}{F_{2}} = \dfrac{ 4}{ 8}$

$\implies \: \dfrac{F_{1}}{F_{2}} = \dfrac{ 1}{ 2}$

$\implies \: F_{1} : F_{2} = 1 : 2$

So, the required ratio is 1 : 2.