A driver applied the break and slow down the velocity of the bus frim 80kmper/hrbto 60kmper/5sec . Calculate the acceleration of the bus
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Answered by
0
u= 80km/HR
= 80*5/18
=22.22m/s
v=60km/hr
=60*5/18
=16.66m/s
t=5 sec
a=v-u/t
=16.66-22.22/5
= 12.216 m/s2
Answered by
2
The car traveled 50 m while accelerating from 0 to 20 m/s in 5 seconds.
The distance d is from
d = v(avg) • t
where v(avg) is the average velocity during the time, or
v(avg) = v(initial) + ∆v/2.
Here v(initial) is 0 and ∆v is 20 m/s, so
v(avg) = 20 m/s / 2 = 10 m/s.
d = 10 m/s • 5 s = 50 m.
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