A driver applies brakes on seeing a traffic signal 400m ahead.At the time of applying the brakes the vehicle was moving with 15 m/s and retarding with 0.3 m/s^2. The distance of vehicle after 1 min from the light is...
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Total distance=400m
V=15m/s,a=0.3m/s^2
V^2-u^2=2as
225/(2×0.3)=s
s=375m
So the car stopped after travelling 375m.
Time taken=v=at
15/0.3=t
t=50s.
The car stops 25m ahead from the signal.so after 1min, it stays there
V=15m/s,a=0.3m/s^2
V^2-u^2=2as
225/(2×0.3)=s
s=375m
So the car stopped after travelling 375m.
Time taken=v=at
15/0.3=t
t=50s.
The car stops 25m ahead from the signal.so after 1min, it stays there
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