A driver applies brakes when he sees a child on the railway track, the speed of the train reduces from 54 km/hr to 18 km/hr in 5 seconds. What is the distance travelled by the train during this interval of time.
aditi232:
are you frm odisha?
Answers
Answered by
37
Hello Friend...
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The answer of u r question is...
Initial speed=u
Final speed =v
Time taken =t
-------------------------------------------
Given,
u= 54 km/hr
v= 18km/hr
t= 5 second.
(60×60) hr=5/3600 hr..
calculate acceleration..
a=(v-u)/t
=(18-54)/(5/3600)
=-25920 km/hr square..
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Equation of motion ...
s=(ut)+(1/2) at 2
s=(54×5/3600)+(1/2)(-25920)(5/3600)2
= 50 m
-------------------------------------------------
so the answer is 50 m
_______________________________
_______________________________
Thank you..⭐️⭐️⭐️
____________________
____________________
The answer of u r question is...
Initial speed=u
Final speed =v
Time taken =t
-------------------------------------------
Given,
u= 54 km/hr
v= 18km/hr
t= 5 second.
(60×60) hr=5/3600 hr..
calculate acceleration..
a=(v-u)/t
=(18-54)/(5/3600)
=-25920 km/hr square..
------------------------------------------------------
Equation of motion ...
s=(ut)+(1/2) at 2
s=(54×5/3600)+(1/2)(-25920)(5/3600)2
= 50 m
-------------------------------------------------
so the answer is 50 m
_______________________________
_______________________________
Thank you..⭐️⭐️⭐️
Answered by
25
Hey Mate! Here's ur answer.
I Hope It Helps.....☺️
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