A driver applies the brake on seeing traffic signal 400m ahead at the time of applying the brakes vehicle was moving with 15m/s and retarding with 0.3m/s (Square). The distance of vehicle after 1 minutes from traffic lights will be what?
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The equations of motion are:
Using relation V2 - u2 = 2*a*S
and Using relation V - U = a*t V:final vel. U: initial vel. a:accln S:distance travelled
The distance travelled before car comes to rest is V=0, U = 15,a=-0.3
S=225/0.6 =375mts
The car comes to rest even before reaching traffic signal.
It comes to rest at 25m ahead traffic signal.
The time taken by car to come to rest is : V/a = 15/0.3 = 50 sec
In 50 seconds car comes to rest
so after 1 min,also car stays 25m ahead of traffic post
option A
Using relation V2 - u2 = 2*a*S
and Using relation V - U = a*t V:final vel. U: initial vel. a:accln S:distance travelled
The distance travelled before car comes to rest is V=0, U = 15,a=-0.3
S=225/0.6 =375mts
The car comes to rest even before reaching traffic signal.
It comes to rest at 25m ahead traffic signal.
The time taken by car to come to rest is : V/a = 15/0.3 = 50 sec
In 50 seconds car comes to rest
so after 1 min,also car stays 25m ahead of traffic post
option A
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