Question

A driver applies the break and slows down the velocity of the bus from 54km/hr to 36km/hr in 5 seconds . calculate acceleration of the bus.

Answer 1

Acceleration(a) =v-u/t
.
. .initial velocity (V) = 54km/hr or 54*5/18=15m/s
Final velocity (u) =36km/hr or 36*5/18=10m/s
So,a=v-u/t
=15-10/5
=5/5
=1m/s^2


.

Answer 2

Acceleration is the change in Velocity

a=v-u/t
V-U=-18kmph = - 5 m/s
T=5s
a=-5/5 m/s^2
a=-1m/s^2

The acceleration is - 1m/s^2