A driver applies the breaks and slows down the velocity of the bus from 80km/h to 60km/h in 5 seconds. Calculate the acceleration of the bus.
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Here ,
The initial velocity (u) of bus = 80km/h = 80×5/18 m/s = 200/9 m/s
The Final velocity (v) of bus = 60km/h = 60×5/18 m/s = 500/3 m/s
Time taken = 5seconds
So, The formula for Acceleration is =
(Final velocity- Initial Velocity )/Time taken
= (500/3 - 200/9) / 5
= {(1500-200)/9)/5
= 1300/9 × 1/5
= 260/9
= 28.8 m/s²
Answer → Acceleration is 28.8m/s²
The initial velocity (u) of bus = 80km/h = 80×5/18 m/s = 200/9 m/s
The Final velocity (v) of bus = 60km/h = 60×5/18 m/s = 500/3 m/s
Time taken = 5seconds
So, The formula for Acceleration is =
(Final velocity- Initial Velocity )/Time taken
= (500/3 - 200/9) / 5
= {(1500-200)/9)/5
= 1300/9 × 1/5
= 260/9
= 28.8 m/s²
Answer → Acceleration is 28.8m/s²
pranjaltripathi1:
Ty but the answer is -1.11m/s^2
Km = 1000 m
1 hr = 3600 sec
Hence, if you multiply the speed in km/hr with 1000/3600, you will get the corresponding speed in m/s
Initial speed = 80 km/hr = 22.22 m/s
Final speed = 60 km/hr = 16.667 m/s
Change of speed = (22.22-16.667) = 5.55 m/s.
This change hapened over 5 seconds. Accelaration is rate of change of speed.
Hence, accelaration = 5.55/5 = 1.11 m/s2
Aravind Menon · 7 years ago
1 hr = 3600 sec
Hence, if you multiply the speed in km/hr with 1000/3600, you will get the corresponding speed in m/s
Initial speed = 80 km/hr = 22.22 m/s
Final speed = 60 km/hr = 16.667 m/s
Change of speed = (22.22-16.667) = 5.55 m/s.
This change hapened over 5 seconds. Accelaration is rate of change of speed.
Hence, accelaration = 5.55/5 = 1.11 m/s2
Aravind Menon · 7 years ago
i think this is the answer
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