a driver can stop his car from red signal at a distance of 20m when he is driving at 36kmph,41.25m when driving at 54kmph.find reaction time
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Given info : a driver can stop his car from red signal at a distance 20 m when he is driving at 36 km/h and 41.25 m when driving at 54 km/h.
To find : time of reaction of car.
Solution : let t is time of reaction.
Using formula, s = ut + u²/2a
case 1 : s = 20m , u = 36 km/h = 36 × 5/18 = 10 m/s
so, 20 = 10t + (10)²/2a
⇒2 = t + 5/a ......(1)
Case 2 : s = 41.25 m, u = 54 km/h = 54 × 5/18 = 15 m/s
so, 41.25 = 15t + (15)²/2a
⇒ 41.25 = 15t + 225/2a
⇒2.75 = t + 7.5/a ......(2)
From equation (1) and (2) we get,
2.75 - 2 = 7.5/a - 5/a
⇒0.75 = 2.5/a
⇒a = 2.5/0.75 = 10/3 m/s²
From equation (1)
2 = t + 5/(10/3)
⇒2 = t + 3/2
⇒t = 0.5 sec
Therefore the time of reaction is 0.5 sec
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