Physics, asked by kumarvedansh3, 11 months ago

A driver decrease the speed of a car from 20 km/s to 15km/s in 6 mins. Find the acceleration of car.

Answers

Answered by Asish5kgf
1

Explanation:

The initial velocity= 20 *10³m/s

The final velocity. =15*10³m/s

Time taken = 360seconds

The acceleration would be ,

v-u/t = 5*10³/360

=25/18

=1.388889m/s²

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Answered by Anonymous
0

acceleration(a) =change in velocity (v-u)/time taken(t)

a=v-u/t

a=15-20/6×60

a=-5/360

a=-1/72

a=0.7 km/s

v=final velocity

u=initial velocity

t=time taken(in seconds)

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