a driver decreases the speed of a car from 25m/s to 5 sec
onds find the acceleration of car
Answers
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0
Answer:
speed =distance upon time
=25/5
=5
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A driver decreases the speed of a car from 25m/s to 10m/s in 5 seconds.find the acceleration of the car?
Answer :
Initial velocity of car, u = 25m/s
Final velocity of car, v = 10m/s
Time taken, t = 5 s
\begin{gathered}formula \: to \: find \: acceleration \: \\ a = \frac{v - u}{t} \\ a = \frac{10 - 25}{5} \\ a = \frac{ - 15}{5} \\ a = - 3m \: per \: s {}^{2} \end{gathered}
formulatofindacceleration
a=
t
v−u
a=
5
10−25
a=
5
−15
a=−3mpers
2
Thus, the acceleration of car is, -3m/s^2. The negative sign of acceleration means that is retardation. So, we can also say that the car has retardation of +3m/s^2.
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