Question

A driver in a bus moving with 40 m/s sees a girl at 25m distance. If he retards bus at 5 m/s2 , can he save the girl or not? solve using equation of motion formula plzzzzz with whole process those who spam will be blocked forever so plz wwrite only if you know answers like i dont know,question not clear will not be accepted and taken strictly into action

Answer 1

Answer:

Explanation:

Retardation = 2 m/s²

Distance traveled = 25 m

Step-by-step explanation :

Given,

u = 36 km/h

= ( 36 *5/18 ) m/s = 10m/s

v = 0

t = 5sec

( i ) retardation of the car

We know,

v = u + at

Substituting the values,

0 = 10 + a*5

0 = 10 + 5a

5a = -10

a = -10 / 5

a= -2 m/s²

Acceleration = -2 m/s²

Since acceleration is negative,

retardation = 2 m/s²

( ii ) distance travelled before it is stopped after applying the brakes

We know,

S = ut + 1/2 at²

Substituting the values,

S = 10*5 + 1/2 * (-2) * (5)²

S = 50 + 1/2* (-2) * 25

S = 50 + 1/2* (-50)

S = 50 + (-25)

S = 25m

So, Distance traveled = 25 m

Hence,

Retardation = 2 m/s²

Distance traveled = 25 m

Hope it helps

:)