Question

A driver initially accelerates the car at 1.8 m/s2
and subsequently at 1.2 m/s2. The ratio of the
forges exerted by the engine will be :​

Answer 1

$\star\:\:\:\large\underline\blue{Given:–}$

A driver initially accelerates the car at 1.8 m/s² and subsequently at 1.2 m/s².

$\star\:\:\:\bf\large\underline\blue{To\:find:—}$

The ratio of the forges exerted by the engine will be = ?

$\star\:\:\:\bf\large\underline\blue{Solution:–}$

Considering mass of car are equal.

We know that,

$\boxed{\bf{\red{F=ma}}}$

$\frac{F₁}{F₂}=\frac{ma₁}{ma₂}=\frac{1.8}{1.2}=\frac{3}{2}$

Therefore,the ratio will be 3:2

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