Question

a driver is driving a car at 36 km/h. when he applies brakes they cause a deceleration of 3m/s. if he takes 1 second to apply the brakes, ___ is the distance travelled by the car during this period
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Answer 1

Answer:

8.5 m

Explanation:

v = u+ at

v = 36×5/18 + (-3)(1)

v = 10-3

v = 7 m/sec

v^2 - u^2 = 2as

7^2 - 10^2 = 2(-3)s

49-100 = -6 s

-51 = -6s

s = 51/6 = 8.5 m