A driver is driving a car at 36 km per hour . when he applies brakes , they cause a deceleration of 3ms-2 . if it takes 1 s to apply the brakes, what is the distance travelled by the car during this period
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Answer:
8.5m
Explanation:
v = u+ at
v = 36×5/18 + (-3)(1)
v = 10-3
v = 7 m/sec
v^2 - u^2 = 2as
7^2 - 10^2 = 2(-3)s
49-100 = -6 s
-51 = -6s
s = 51/6 = 8.5 m
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