A driver leaves a city at 6 a.m. and another driver leaves the city from the same place at
11:30 a.m. in the same direction. If the average speed of the first driver was 55 km/h and the second
driver was 62 km/h, find the time at which they will be together.
Answers
Answered by
5
Answer:
they will be together at 5:45 p.m on the next day As the second driver leaves at( 11:30a.m -6 am)= 5.5 hours after the first driver. so the time duration for second driver is (t -5.5) hours.
If my answer is correct please make me brainlest
Answered by
7
Answer:
6:42am the day after next day
Step-by-step explanation:
S=D/t
55=D/t
62=D/(t-5.5)
t=48.71 hours
which is @ 6:42am the day after next day
if they started at Day-1 they'll meet at Day-3
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