Question

A driver leaves a city at 6 a.m. and another driver leaves the city from the same place at
driver was 62 km h, find the time at which they will be together.
11:30 a.m. in the same direction. If the average speed of the first driver was 55 km/h and the second driver was 62 km/h .find the time at which they will be together.
please sir write this question in copy and full method then i give you brain list please sir​

Answer 1

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Let t be the time after 6 a.m. when first driver leaves.

The second drives leave at 11.30, that means he leaves (11.30-6:00=5.5hr) after the first driver, so the time duration for the second driver =t-5.5 hrs

The average of first driver is 62km/hr ans of second driver is 55km/hr

Distance= speed×time

So,

55t=62×(t-5.5)

55t=62t-341

55t-62t= -341

-7t= -341

$\sf \: t = \frac{ \cancel - 341}{ \cancel - 7} = 48.71$

So they will together leave after 48.71 hrs after 6 a.m. which is at (6 hr 0 minutes+41 hr 71 minutes= 12:11 p.m.(noon) on the third day(means the day after tomorrow))

${\underline{❥ʜᴏᴘᴇ \: ɪᴛ \: ʜᴇʟᴘs \: ʏᴏᴜ.....}}$