Question

a driver leaves is city at 6 a.m. and another driver the city from the same place at 11:30 a.m. in the same direction . if the average speed of the first driver was 55 km/hour and the second driver 65 km/hour. find the time at which they will be together​

Answer 1

Answer:

A driver leaves is city at 6 a.m

before another driver starts from the city first driver travels x kms

s=d/t

55=d/5.5hrs

d=302.5 kms

meeting time of both the drivers= distance/relative speed

time=302.5/7

43.21hrs

answer=11.30 am + 43.21 hours

Step-by-step explanation:

Please mark me as brainliest answer .

Answer 2

QUESTION:-

a driver leaves is city at 6 a.m. and another driver the city from the same place at 11:30 a.m. in the same direction . if the average speed of the first driver was 55 km/hour and the second driver 65 km/hour. find the time at which they will be together​

GIVEN:-

• a driver leaves is city at 6 a.m.
• another driver the city from the same place at 11:30 a.m
• average speed of the first driver was 55 km/hour
• average speed of the second driver 65 km/hour

TO FIND:-

• the time at which they will be together​

SOLUTION:-

A driver leaves is city at 6 a.m

before another driver starts from the city first driver travels x kms

s=  $\frac{D}{T}$

$55 = \frac{d}{5.5} hours \\d = 302.5 km$  

meeting time of both the drivers= $\frac{distance}{relative speed}$

time= $\frac{302.5}{7}$

43.21hours

ANSWER:-

11.30 am + 43.21 hours

                                    Hope it helps :D