Question

A driver of a car travelling at 54 km/h applies the brakes and stops in 5 seconds. Find the

acceleration of car.​

Answer 1

Answer:

Explanation:

Initial velocity= 54×5/18

= 15 m/sec

Now stopping time t°

t°= u/-a(retardation)

So as per the question

-a = 3

acceleration is -3

Answer 2

Given :

• Initial velocity ( u ) = 54 km/hr
• Final velocity ( v ) = 0 km/hr
• Time = 5 sec

To Find :

• Acceleration of the car ( a )

Solution :

$\Large \underline{ \orange{ \tt v = u + at}} \\ \\ \implies \tt0 = 54 + 5a \\ \\ \tt \implies 5a = - 54 \\ \\ \tt \implies a = \frac{ - 54}{5} \\ \\ \large \implies\boxed{ \green{ \tt a = - 10.8 \: {ms}^{ - 2} }}$

$\large\underline{\bf \blue{Acceleration \: of \: car \: is \: - 10.8 \: {ms}^{ - 2} }}$