Question

A driver of athree wheeler moving with a speed of 36 km per hr sees a child in the middle af road and brings his vehicle at rest in 0.4 secs just in time to save the child .the average retarding force on the vehicle is ( mass ofvehicle is 400 kg and of driver is 65 kg)

Answer 1

here is your answer -

we know that vehicle is moving with 36km/h
so, u = 36, = 10m/sec.
final velocity = 0
t = 0.4sec.
so, by v= u+at
0 = 10+(-a)0.4
a4/10 = 10
a = 100/4
a = 25m/sec²
here a is retardation..
so, for retardation force =
f = m(retardation)
f = 465×25
f = 11625 kgmeter/sec² or Newton..

Answer 2

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u = 36 km/h

v = 10 m/s

t = 4 s

Mass of three- wheeler, m = 400 kg

Mass of the driver, m' = 65 kg

Total mass of the system, M = 400 + 65 = 465 kg

▪Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v = u + at

=> a= v- u / t = (0-10)/4 = -2.5 m/s^2

◾The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

◾Using Newton’s second law of motion, the net force acting on the three-wheeler can be calculated as:

F = Ma = 465 × (–2.5) = –1162.5 N

◾The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.

I hope, this will help you___❤❤

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