A driver of train A, moving at a speed 30 ms–1, sights another train B going on the same
track and in the same direction with speed 10 ms–1. He immediately applies brake that gives
his train a constant retardation of 2 ms–2. What must be the minimum distance between
trains in order to avoid a collision
Answers
Answer:
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Explanation:
Answer: to avoid collision the minimum distance must be 100m Explanation: Speed of train A = v1 = 30 m / s Speed of train B = v2 = 10m / s The train which is moving with speed v1 should stop completely before reaching the second train which is moving with speed v2. Relative speed of first train with respect to the second train = (v1 - v2) Relative speed between two trains = v1 V2 = 30 -10 = 20m / s The train slows down when brakes are applied and comes to hault Acceleration = 2m / s2 V = O m / s
retardation a, distance s and relative velocity are related by the equation of motion "v2 = u2 -2aS", where v is final velocity which is zero in this case, u is initial velocity, a is retardation and S is distance traveled. hence with the given information, we get the condition for stopping of first train when it just reaches the second train as given below v2 = u2-2as 02 = 20x20 - 2 (-2) xs -400 = -45 S = 400/4 S = 100m Hence to avoid collision the minimum distance must be 100m
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