A driver of train travelling at 40 m/s applies the brakes as a train enter a station The train slows down at the rate of 2m/s The platform is 400 m long will the train stop in time
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Given,
a = -2m/s²
u = 40m/s
s = 400m
v = 0 (as the train stops)
By applying s = ut + 1/2at²
400 = 40t - 1/2 × 2t²
t = 20 sec.
The train will stop in 20 seconds.
a = -2m/s²
u = 40m/s
s = 400m
v = 0 (as the train stops)
By applying s = ut + 1/2at²
400 = 40t - 1/2 × 2t²
t = 20 sec.
The train will stop in 20 seconds.
AnmolKamboj11:
can you solve please last calculation of 40t-1/2atsquare
please.
yes but I don't understand calculation
Please send me full calculation please!
As it possible for you can send me calculation today present
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