Math, asked by purushothamannataraj, 4 months ago

a driver speedometer shows that this car is travelling at 60 kilometre per hour when it is actually moving at 62 kilometre per hath then relative error is what​

Answers

Answered by krishnanmridu
0

Answer:

Step-by-step explanation:

Car A speed =60km/hr=60x5/18=50/3 m/s

Car B speed =42km/hr=42x5/18=35/3 m/s

Relative speed of Car A w.r.t Car B is =50/3 - 35/3=15/3=5 m/s

Total distance to be covered in overtaking = Length of both cars =10m

Time =Distance/speed=10m/5m/s=2 sec

Total distance used for overatking will be equal to distance covered by car in overtaking + length of car

=(50/3)x2+5

=100/3 +5

=33.3+5

=38.3 m

∴time taken during the overtake and the total road distance used for the overtake is 38.3m

Answered by ashokkumar0902
0
  1. this is the amsher I thing it's helpful for you
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