Question

A driver starts his packed car within 5 seconds reaches a speed of 60 km/h, as he travels east. What is his acceleration?

Answer 1

Answer:

3.333 m/s²

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Final velocity = v = 60 km/hr

• Time taken = t = 5 seconds

To find :

• Acceleration of the car

Acceleration = (v-u) / t

V = 60 km/hr = 60×5/18 = 50/3 m/s

Acceleration = (50/3-0)/5

Acceleration = 50/3/5

Acceleration = 50/3×1/5

Acceleration = 50/15

Acceleration = 3.333 m/s²

The acceleration of the car is equal to 3.33 m/s²

Answer 2

$\huge{ \bold{ \underline{ \underline{ \red{Question:-}}}}}$



▪ A driver starts his packed car within 5 seconds reaches a speed of 60 km/hr, as he travels East. What is his acceleration?




${ \bold{ \huge{ \underline{ \underline{ \red{Solution:-}}}}}}$



${ \bold{ \orange{GIVEN- }}}$



• since the car was packed i.e., initially it was at rest



★ initial velocity (u) = 0


★ final velocity (v) = 60km/hr


= 60*5/18 m/sec


= 16.67 m/sec


★ Time (t) = 5 seconds



${ \bold{ \orange{TO \: FIND- }}}$



➡ Acceleration??



${ \star{ \bold{ \blue{ \underline{ \: \: \: acceleration \: (a)}}}}}$



▪ The rate of change of velocity is known as acceleration.


▪ It is a vector quantity.



${ \underline{ \boxed{ \bold{ \red{ \: \: a = \frac{v - u}{t} \: \: }}}}}$


where,


➧ a = acceleration

➧v = final velocity

➧ u = initial velocity

➧ t = time



• substituting the above given values in the formula...



${ \bold{a = \frac{16.67m {sec}^{ - 1} - 0 \: \: \: }{5 \: sec}}}$



${ \bold{ \implies{a = \frac{16.67 \: m \: {sec}^{ - 1} }{5 \: sec}}}}$



${ \boxed{ \boxed{ \bold{ \implies{ \blue{a = 3.33 \: m {sec}^{ - 2} }}}}}}$