Question

A driver starts his parked car and within 1 minute reaches a velocity of 60 miles per hour east . What is his acceleration?

Answer 1

Answer:

Hey mate,

Here is your answer,. ⬇️ ⬇️

{ANSWER :-}ANSWER:−

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< i ><i> Here, we have that the car was at rest.

Thus, initial velocity(u) = 0 m/s

In 5 seconds, it reaches speed of 60 km/h.

Thus, time taken(t) = 5 seconds.

And final velocity (v) = 60 km/h = (60*1000)/(1*60*60) m/s = 1000/60 m/s.

Therefore, Acceleration(a) = (v - u) /t

=> a = ( 1000/60 - 0) /5

=> a = 1000/60 * 1/5 = 200/60

=> a = 20/6 = 10/3 = 3.3

Thus, Acceleration is 3.3 m/s^2.

➡️ Hence, the Acceleration is 3.3 m/s^2 .

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➡️Or, you may do like this,

Initial velocity(u) = 0 km/h.

Final velocity(v) = 60 km/h

And time taken(t) = 5 seconds = 1/12 hour.

Thus, Acceleration is

= (v-u) /t

= ( 60 - 0) / (1/12)

= 60*12

= 720 km/h^2.

➡️ Hence, the Acceleration is 720 km/h^2

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< b ><b> Both the process are correct, the measuring unit varies.

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Hope this helps,.

If helps, please mark 'thanks'

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REGARDS, ✌️

THANK YOU

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