Question

A driver starts his parked car and within 5 Seconds reaches a speed of 60 km/h, as he travels east. What is his acceleration?

Answer 1

6km=600m
so by 1st equation of motion
v=u+at
600=0+a5
5a=600
a= 600÷5=120m/s²

Answer 2

Heya mate,

Here is your answer,. ⬇️ ⬇️

${ANSWER :-}$

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$<i>$ Here, we have that the car was at rest.
Thus, initial velocity(u) = 0 m/s

In 5 seconds, it reaches speed of 60 km/h.
Thus, time taken(t) = 5 seconds.
And final velocity (v) = 60 km/h = (60*1000)/(1*60*60) m/s = 1000/60 m/s.

Therefore, Acceleration(a) = (v - u) /t

=> a = ( 1000/60 - 0) /5

=> a = 1000/60 * 1/5 = 200/60

=> a = 20/6 = 10/3 = 3.3

Thus, Acceleration is 3.3 m/s^2.

➡️ Hence, the Acceleration is 3.3 m/s^2 .

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➡️Or, you may do like this,
Initial velocity(u) = 0 km/h.
Final velocity(v) = 60 km/h
And time taken(t) = 5 seconds = 1/12 hour.

Thus, Acceleration is
= (v-u) /t
= ( 60 - 0) / (1/12)
= 60*12
= 720 km/h^2.

➡️ Hence, the Acceleration is 720 km/h^2
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$<b>$Both the process are correct, the measuring unit varies.

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Hope this helps,.

If helps, please mark 'thanks'

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REGARDS, ARNAB ✌️

THANK YOU