A driver takes 0.2 s to apply brakes. If he is driving at a speed 54km/hr and the brakes cause a deceleration of 6m/s^2 find the distance travelled by the car,after he sees the need to apply brakes
Answers
Answered by
8
54km/h = 15m/s
S1 = ut
= 15 * 0.2
= 3 m
S2 = u^2 / (2a)
= (15)^2 / (2 * 6)
= 225/12
= 18.75 m
S = S1 + S2
= 3.0m + 18.75m
= 21.75 m
S1 = ut
= 15 * 0.2
= 3 m
S2 = u^2 / (2a)
= (15)^2 / (2 * 6)
= 225/12
= 18.75 m
S = S1 + S2
= 3.0m + 18.75m
= 21.75 m
Answered by
3
Speed = 54km/h =
15m/s
time = 0.2Sec
We know that
S= ut
S1= 15 × 0.2
u = 3m
S2 = u² / 2 a )
= 15² / 2 × 6
= 225/ 12
= 18.5
S = s1 + s2
= 3 + 18.75
= 21.75m
15m/s
time = 0.2Sec
We know that
S= ut
S1= 15 × 0.2
u = 3m
S2 = u² / 2 a )
= 15² / 2 × 6
= 225/ 12
= 18.5
S = s1 + s2
= 3 + 18.75
= 21.75m
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