a driver takes 0.20 seconds to apply the brakes. if he is driving a car at a speed of 54 kmh . and the brakes cause a deceleration of 6.0 ms . find the distance traveled by the car after he sees the need to put the brakes
Answers
Answered by
17
t=0.20 s
u=54kmph or 15mps
a= -6mps
so, wkt
s=ut+1/2at^2
putting the value
s=15(.2)+1/2(-6)(.04)
s=3-1.2
s=1.8m
u=54kmph or 15mps
a= -6mps
so, wkt
s=ut+1/2at^2
putting the value
s=15(.2)+1/2(-6)(.04)
s=3-1.2
s=1.8m
Answered by
5
Answer:
Explanation:
s = ut + 1/2 at ^2
S Distance (x)
U Initial velocity (54 km/h)
T Time (0.20 s)
A Acceleration (-6 )
=> x = (54 * 0.20) + 1/2 * -6 * (0.20 * 0.20)
= 10.8 + 1/2 * -24
= 10.8 + (-12)
= 1.2 M
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