Question

A driver travelling at 20 m/s observes an accident ahead and takes 0.50 seconds to apply the brakes. The brakes slow the car down with an acceleration of -5.0 m/s2. Calculate the total stopping distance of the car.

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Answer 1

16.25m

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Answer 2

$\mathtt\red{Given}$$\red{\longrightarrow}$

Initial velocity =20m/s

Time Taken=0.50 seconds

Final velocity=0m/s

$retardation = - 5 {ms}^{2}$

$\mathtt\pink{To Find}$$\pink{\longrightarrow}$

Distance travelled

$\mathtt\purple{Solution}$$\purple{\longrightarrow}$

$s = ut + \frac{1}{2} a {t}^{2}$

$s = 20 \times 0.5 + \frac{1}{2} \times( - 5) \times ( {0.5)}^{2}$

$s = 10× \frac{1}{2} \times ( - 5) \times 0.25$

$s = 6.25m$