A driver travelling at speed 36 kmh-' sees the light turn red at the intersection. If his reaction time is
0.6s, and then the car can deaccelerate at 4ms. Find the stopping distance of the car.
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total braking distance will be 18.5m.Follow me if u understud!!
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Answer:
Explanation:
36x5/18=10ms(from khm/hr to m/s)
so,
u=10ms reacn.time (t)=0.6s v=0 s=?
step1⇒ distance travelled in reaction time→
⇒ s=uxt ⇒ s=10x0.6 ⇒ 6m.
step2⇒ distance travelled in deaccln. time→
v²=u²+2as
s=v²-u²÷2as
s= 0-(10)²÷2x(-4) ⇒ s=12.5m
adding step1 and step2 (i.e total distance)
12.5+6⇒18.5m
hope it helps you! thank you!
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