Question

A driver travels 10 Km in 15 minutes, stops for a 15-minute break, then travels an additional 60 Km in 45 minutes. 1. Calculate his average speed for a. The first 15 minutes of his journey b. The last 45 minutes of his journey c. The entire journey.

Answer 1

Answer:

1. a. 11.11

b. 22.22

c. 33.33

Explanation:

AVERAGE SPEED IS TOTAL DISTANCE TRAVELED DIVIDE BY TIME TAKEN

1. <V1> = 10000÷15÷60
2. <V2> = 60000÷45÷60
3. <V3> = <V1>+<V2> = 11.11+ 22.22

Answer 2

Answer:

time taken for first 10km = 15min = 0.25hr

avearage speed for first 15min = total distance /time taken = 10/0.25 = 40km/hr

time taken for last 60km =45min =0.75hr

avearage speed for last 45min = 60/0.75 = 80km/hr

time taken for total journey = 75min = 1.25hr

average speed for total journey = 60+10/1.25 = 56km/hr

Explanation:

average speed = total distance/time taken