A driver was driving a car with speed of 54 km/hour. Suddenly he noticed a monkey 57 m ahead. Instantly he applied brake. As a result the car stopped 75 cm infront of the monkey. Calculate acceleration and time to stop the car
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Initial velocity(u) : 54 km/hr
=54 * 5/18
= 15 m/s
Final velocity(v) : 0 m/s
Distance(s) : 57m - 75cm
= 57 - 3/4
= 225/4 m
Formula :
v² = u² + 2as
= 0² = 15² + 2 * a * 225/4
= 0 = 225 + 112.5a
→ a = -225/112.5
= a = -2m/s²
Acceleration is negative showing retardation.
Formula :
v = u + at
= 0 = 15 + (-2) * t
= 0 = 15 - 2t
→ 2t = 15
= t = 7.5 sec
Time taken is 7.5 seconds
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=54 * 5/18
= 15 m/s
Final velocity(v) : 0 m/s
Distance(s) : 57m - 75cm
= 57 - 3/4
= 225/4 m
Formula :
v² = u² + 2as
= 0² = 15² + 2 * a * 225/4
= 0 = 225 + 112.5a
→ a = -225/112.5
= a = -2m/s²
Acceleration is negative showing retardation.
Formula :
v = u + at
= 0 = 15 + (-2) * t
= 0 = 15 - 2t
→ 2t = 15
= t = 7.5 sec
Time taken is 7.5 seconds
If it helped, Press the thank you button.
Follow me for the most simplified answers.
iftakhermahmud:
thanks u soo much
If it helped, Press the thank you button.
Follow me for the most simplified answers.
Follow me for the most simplified answers.
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