A drone camera is used to shoot an object P from two different positions R and S along the same vertical line QRS. The angle of depression of the object P from these two positions are 35° and ° respectively as shown in the diagram. If the distance of the object P from point Q is 50 metres, then find the distance between R and S correct to the nearest meter.
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The answer is 52 meters.
GIVEN
Drone camera is used to shoot an object P from two different positions R and S along the same vertical line QRS. The angle of depression of the object P from these two positions are 35° and ° respectively as shown in the diagram. If the distance of the object P from point Q is 50 metres.
TO FIND
Find the distance between R and S
SOLUTION
We can simply solve the above problem as follows;
In ∆PRQ
tan(35) = RQ/PQ
0.7 = RQ/50
RQ = 0.7002 × 50 = 35.01m
In ∆PSQ
tan(60) = SQ/PQ
1.73 = SQ/50
SQ = 1.73 × 50 = 86.5m
RS = SQ - RQ = 86.5 - 35.01 = 51.49 ≈ 52 meter
Hence, The answer is 52 meters.
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