Science, asked by rilwan2606, 7 months ago

A drone of mass 10 kg has a vertical acceleration of 10 m/s2 . The drone is carrying 300g of equipment inside it. What is the direction and magnitude of the ( i ) net force exerted by the equipment on the drone’s floor. ( ii ) action of the drone’s rotors in the air surrounding it. ( iii ) net force exerted on the drone by the surrounding air

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Answered by shriya619
0

Explanation:

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11th

Physics

Work, Energy and Power

Introduction to Work

An object mass 10 kg falls ...

PHYSICS

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Asked on December 27, 2019 by

Geeta Saksena

An object mass 10 kg falls from rest through a vertical distance of 10 m and acquires a velocity of 10 m/s. The work done by the push of air on the object is (g=10m/s

2

).

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ANSWER

Given that,

Mass of object, m=10Kg

Velocity, v=10m/s

Vertical distance, h=10m

From work energy theorem:

Work done by weight + work done by air = KE

W

air

=KE−W

weight

=

2

1

mv

2

−mgh

=

2

1

×10×10×10−10×10×10

=−500J

The work done by the push of air on the object is -500 J.

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