A drone of mass 10 kg has a vertical acceleration of 10 m/s2 . The drone is carrying 300g of equipment inside it. What is the direction and magnitude of the ( i ) net force exerted by the equipment on the drone’s floor. ( ii ) action of the drone’s rotors in the air surrounding it. ( iii ) net force exerted on the drone by the surrounding air
Answers
Answered by
0
Explanation:
What would you like to ask?
11th
Physics
Work, Energy and Power
Introduction to Work
An object mass 10 kg falls ...
PHYSICS
avatar
Asked on December 27, 2019 by
Geeta Saksena
An object mass 10 kg falls from rest through a vertical distance of 10 m and acquires a velocity of 10 m/s. The work done by the push of air on the object is (g=10m/s
2
).
MEDIUM
Share
Study later
ANSWER
Given that,
Mass of object, m=10Kg
Velocity, v=10m/s
Vertical distance, h=10m
From work energy theorem:
Work done by weight + work done by air = KE
W
air
=KE−W
weight
=
2
1
mv
2
−mgh
=
2
1
×10×10×10−10×10×10
=−500J
The work done by the push of air on the object is -500 J.
Similar questions
English,
3 months ago
English,
7 months ago
English,
7 months ago
Computer Science,
11 months ago
Biology,
11 months ago