A drop of 0.05 ml hcl falls on aluminim find max area of hole produced
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Meq of Al=Meq of HCl
=12×0.05=0.6
Weight of Al=0.6×91000=0.0054g
Volume of Al foil=0.00542.7cm3
=0.002cm3
Area× thickness=volume
Area=0.0020.01=0.02cm2
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