Question

a drop of water of diameter 12mm breaks into number of droplets each of diameter 2mm.how many droplets will be formede?​

Answer 1

Here the volume of water droplets is conserved, so we can form an equation,

$\displaystyle\longrightarrow\sf {\dfrac {4}{3}\pi(12)^3=n\cdot\dfrac {4}{3}\pi(2)^3}$

where the water drop is assumed to be spherical in shape.

From the equation we get,

$\displaystyle\longrightarrow\sf {n=\dfrac {12^3}{2^3}}$

$\displaystyle\longrightarrow\sf {\underline {\underline {n=216}}}$