Question

- A drop pf mass 4.8 x 10-1 g having charge
2.4 x 10-18 coulomb on it, is suspended in
balanced state between two horizontal charged
plates. Distance between the plates is 1.0 cm.
Calculate the potential difference between the
plates.
​

Answer 1

The potential difference between the plates is  zero.

To calculate the potential difference between the plates, we can use the equation:

Potential difference = Force / Charge

The force on the droplet is the electrostatic force due to the charges on the plates, which is given by Coulomb's Law:

$F = (k * q1 * q2) / d^2$

where k is the Coulomb constant, q1 and q2 are the charges on the plates, and d is the distance between the plates.

Since the droplet is in a balanced state, the force on it due to the charges on the plates is zero. Therefore, the potential difference between the plates is also zero.

V = 0

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Answer 2

A drop pf mass 4.8 x 10-1 g having charge

2.4 x 10-18 coulomb on it, is suspended in

balanced state between two horizontal charged

plates. Distance between the plates is 1.0 cm.

Calculate the potential difference between the

plates.