A drowning pin is pushed against a wooden table with a force of 10 N. Calculate the pressure of a pin on the point of the table If the area of the pin is 0.01 sq mm
prekshamehta:
apply formula pressure is force per unit area
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0
Force applied=10N
area of pin=0.01sqmm=0.01×10^-3 sq=10^-8
pressure=force/area=10/10^-8=10^9N/m^2
area of pin=0.01sqmm=0.01×10^-3 sq=10^-8
pressure=force/area=10/10^-8=10^9N/m^2
Answered by
3
Force = 10N
area = 0.01mm² = 1×10⁻⁸ m²
Pressure = F/A = 10/(1×10⁻⁸) = 1×10⁹ N/m² = 1GPa
area = 0.01mm² = 1×10⁻⁸ m²
Pressure = F/A = 10/(1×10⁻⁸) = 1×10⁹ N/m² = 1GPa
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