Question

A drug is allowed to equilibrate with a mixture of octanol and water for 1 hour. The concentration of the drug in octanol layer is 3.5 as much as in the water layer. Calculate the Log P of the drug​

Answer 1

Answer:

0.5441

Explanation:

p = concentration of drug in octanol / concentration of drug in water

here, p = 3.5/1

so, Log P = 0.5441

Answer 2

Given,

Time to equilibrate= 1 hour

The concentration of the drug in octanol layer = 3.5 (concentration in water layer)

To find,

log(p) of the drug

Solution,

We can solve this numerical problem by using the following process.

We know that,

We all know that the pharmaceuticals you will be prescribed regularly and with which you will become acquainted are known as P(ersonal)-drugs. The P-drug idea encompasses a drug's name, dose form, dosing schedule, and length of therapy for an ailment.

The value of p for a drug is estimated by dividing the drug concentration in the octanol layer by the drug concentration in the water layer.

Thus,

The p-value of the drug = 3.5

p = 3.5

log(p) = log(3.5)

          = 0.5441

As a result, the value of log(p) of the drug is 0.5441.