Math, asked by ArghaMukherjee, 8 months ago

A drum contained 160 litres of kerosene. 10 litres of kerosene was lost due to leakage. What percent of kerosene remained in the drum?​

Answers

Answered by sujashmalda2080
9

Answer:

100-(100/16)=100-6.25=93.75

Step-by-step explanation:

160 litres of kerosene = 100%

1litre of kerosene = (100/160)%

so that, 10litres of kerosene = {(100×10)/160}%=(100/16)% = 6.25%

6.25% of kerosene is leaked out of the drum.

so that, kerosene remained in the drum = (100- 6.25)% = 93.75%

Answered by samir933101
1

Answer:

a drum contained 16o lit 10 lit lost what percent of litre

is lef

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