A drum contained 60 litres of milk. Out of this, 15.75 litres of milk was taken out in one basket and 8.5 litres in another bucket. How much milk is left in the drum
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- Amount of milk in the vessel= 60 Litres. Now amount of milk removed is 12- Litres and subsequently amount of water added is 12 litres. So 12/60= 1/5 of the milk is replaced by water. So the portion of milk remaining in the vessel= (1–1/5) = 4/5.
- This process is now repeated two - times. So the portion of milk in the second and the final stage = (1-1/5)^2. = (4/5)^2=[ 4/5 x 4/5]= 16/25.
- The volume of water in the final stage will be (1–16/25)= 9/25.
- So the ratio of milk-water in the resultant mixture= 16/25 : 9/25
- = 16:9 ========××××××××==========×××××
- So one can use the formula
- (1-x)^n. ; Where
- x= fraction of milk that is removed and the same fraction of water added to the milk.
- n= Number of times this process is continued. =====×××××======××××××=====×××××
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